1z0-001 Exam

9i Internet Application Developer Introduction to Oracle: SQL and PL/SQL

  • 科目编号:1z0-001
  • 科目名称:9i Internet Application Developer Introduction to Oracle: SQL and PL/SQL
  • 考题数目:171 Q&As
  • 更新日期:2010-05-16
  • 价 格 : ¥ 462.00 ¥ 413.00

免费下载 1z0-001 认证考题Demo

下载 1z0-001 PDF 认证考试题库
考试引擎下载

 

选择 pass4side 1z0-001 题库

1z0-001 考试是 Oracle 公司的 9i Internet Application Developer Introduction to Oracle: SQL and PL/SQL 认证考试官方代号,pass4side 的 1z0-001 权威考试题库软件是 Oracle 认证厂商的授权产品,pass4side 绝对保证第一次参加 1z0-001 考试的考生即可顺利通过,否则承诺全额退款!

1、Pass4Side考题大师1z0-001试题都是考试原题的完美组合,覆盖率95%以上,答案由多位专业资深讲师原版破解得出,正确率100%,只要您使用本站的考试题库参加1z0-001 考试,我们保证您一次轻松通过考试;

2、售后服务第一!我们相信要想在当今时代取得成功,必须为广大用户提供全套的周到细致的全程优质售后服务,只有客户满意了,我们才能发展。客户至上是我们Pass4Side考题大师的一贯宗旨;

3、Pass4Side实行“一次不过全额退款”承诺。如果您购买我们1z0-001的考题,只要不是首次通过,凭盖有PROMETRIC或VUE考试中心钢印的考试成绩单,我们将退还您购买1z0-001考题大师的全部费用,绝对保证您的利益不受到任何的损失;

4、本站1z0-001题库根据1z0-001考试的变化动态更新,在厂家考题每次发生变化后,我们承诺2天内更新1z0-001题库。在您购买我们的产品之后,我们将提供90天的免费更新。确保1z0-001考题的覆盖率始终都在95%以上;我们提供2种 1z0-001 考题大师版本供你选择。

5、软件版本1z0-001 考试题库
优点:具有学习模式,测试模式,线上自动升级
缺点:仅限固定电脑使用,不可打印为文本,只能PC阅读

6、PDF 格式1z0-001 考试题库(部分最新更新科目已不提供PDF)
优点:不需下载安装软件,方便用户打印和携带,但也带来了可随意制的弊端,因此我们提醒用户不得随意公开或出售本站的1z0-001题库,一经发现立即取消其升级资格,且不予退款。
缺点:不具备测试模式,通过查看 pass4side.cn网站及查收我们的更新E-MAIL获取更新信息。
 
 
Exam : Oracle 1Z0-001
Title : INTRODUCTION TO ORACLE: SQL AND PL/SQL


1. Click on the EXHIBIT button and examine the structure of the DEPARTMENT and EMPLOYEE tables.
Evaluate this SQL statement:
CREATE INDEX emp_dept_id_idx
ON employee(dept_id);
Which result will the statement provide?
A. Store an index in the EMPLOYEE table.
B. Increase the chance of full table scans.
C. May reduce the amount of disk I/O for SELECT statements.
D. May reduce the amount of disk I/O for INSERT statements.
E. Override the unique index created when the FK relationship was defined.
Answer: C

2. Which should you do after each FETCH statement in a PL/SQL block?
A. Open the cursor.
B. Close the cursor.
C. Initialize the loop.
D. Test for rows using a cursor attribute.
Answer: D

3. Given this executable section of a PL/SQL block:
BEGIN
FOR employee_record IN salary_cursor LOOP
employee_id_table(employee_id) :=
employee_record.last_name;
END LOOP;
CLOSE salary_cursor;
END;
Why does this section cause an error?
A. The cursor needs to be opened.
B. No FETCH statements were issued.
C. Terminating conditions are missing.
D. The cursor does not need to be closed.
Answer: D

4. Click on the EXHIBIT button and examine the table instance chart for the cars table.
Which SELECT statement will display style, color, and lot number for all cars based on the model entered at the prompt, regardless of case?
A. SELECT style, color, lot_no
FROM cars
WHERE model = UPPER('&model');
B. SELECT style, color, lot_no
FROM cars
WHERE model = '&model';
C. SELECT style, color, lot_no
FROM cars
WHERE UPPER(model) = UPPER('&model');
D. SELECT style, color, lot_no
FROM cars
WHERE UPPER(model) = '&model';
Answer: C

5. The EMPLOYEE table contains these columns:
BONUSNUMBER(7,2)
DEPT_ID NUMBER(9)
There are 10 departments and each department has at least 1 employee. Bonus values are greater than 500; not all employees receive a bonus.
Evaluate this PL/SQL block:
DECLARE
v_bonusemployee.bonus%TYPE := 300;
BEGIN
UPDATE employee
SET bonus = bonus + v_bonus
WHERE dept_id IN (10, 20, 30);
COMMIT;
END;
What will be the result?
A. All employees will be given a 300 bonus.
B. A subset of employees will be given a 300 bonus.
C. All employees will be given a 300 increase in bonus.
D. A subset of employees will be given a 300 increase in bonus.
Answer: D

6. Click on the EXHIBIT button and examine the table instance chart for the patient table.
You need to create the patient_id_seq sequence to be used with the patient table's primary key column. The sequence should begin at 1000, have a maximum value of 999999999, never reuse any numbers, and increment by 1.
Which statement would you use to complete this task?
A. CREATE SEQUENCE patient_id_seq
START WITH 1000
MAXVALUE 999999999
NOCYCLE;
B. CREATE SEQUENCE patient_id_seq
START WITH 1000
MAXVALUE 999999999
STEP BY 1;
C. CREATE SEQUENCE patient_id_seq
ON patient (patient_id)
MINVALUE 1000
MAXVALUE 999999999
INCREMENT BY 1
NOCYCLE;
D. This task cannot be accomplished.
Answer: A

7. The structure of the DEPT table is as follows:
Name Null? Type
------------------------------- -------- -------
DEPTNO NOT NULL NUMBER(2)
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
Examine the code:
DECLARE
TYPE dept_record_type IS RECORD
(dno NUMBER,
name VARCHAR2(20));
dept_rec dept_record_type;
BEGIN
SELECT deptno, dname
INTO dept_rec
FROM dept
WHERE deptno = 10;
END;
Which statement displays the name of the selected department?
A. DBMS_OUTPUT.PUT_LINE(name);
B. DBMS_OUTPUT.PUT_LINE(dname);
C. DBMS_OUTPUT.PUT_LINE(dept_rec.name);
D. DBMS_OUTPUT.PUT_LINE(dept_rec.dname);
E. DBMS_OUTPUT.PUT_LINE(dept_rec(name));
Answer: C

8. You issue this command:
CREATE SYNONYM emp
FOR ed.employee;
Which task has been accomplished?
A. The need to qualify an object name with its schema was eliminated for user Ed.
B. The need to qualify an object name with its schema was eliminated for only you.
C. The need to qualify an object name with its schema was eliminated for all users.
D. The need to qualify an object name with its schema was eliminated for users with access.
Answer: B

客户反馈

I have finally passed the exam!TestInside gave me hopness,I have fell in love with it! Norton - 2009-07-03 23:40:33


产品保证 | 购买指南 | 常见问题 | 支付方式 | 退款协议 | 考试引擎 | 联系我们 | 站点地图 1 2 3 4

Copyright©2006-2009 Pass4side Limited. All Rights Reserved

Pass4side materials do not contain actual questions and answers from Microsoft's Cisco's Certification Exams.